I thought I got how to do stress, yet I was wrong. My answers were totally off the right answers. Could someone please show me clearly step by step how to get the right answers provided for my future refrence? Please and thank you to physic geniuses.
A) How much stress is exerted on a road by an 18-wheel truck which has a mass of 15 x 10^3 kg and a footprint area for each tire of 0.04 m^2? (Answer: 2.04 x 10^5 N/m^2)
B) A 1200 kg auto is supported by 4 tires, each with an area of 0.015 m^2. How much stress does this cause on the road?
C) If the truck driver from part A raised 4 of the wheels so they wouldn't touch teh ground, this would reduce tire wear. However, what would be the new stress on the road? (Answer: 2.63)
A) How much stress is exerted on a road by an 18-wheel truck which has a mass of 15 x 10^3 kg and a footprint area for each tire of 0.04 m^2? (Answer: 2.04 x 10^5 N/m^2)
B) A 1200 kg auto is supported by 4 tires, each with an area of 0.015 m^2. How much stress does this cause on the road?
C) If the truck driver from part A raised 4 of the wheels so they wouldn't touch teh ground, this would reduce tire wear. However, what would be the new stress on the road? (Answer: 2.63)
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A.
in the first question, stress is simply the pressure exerted by the truck on the road...
so stress will b = force (in this case weight=m*g)/total area(18*0.04)
P=15*10^3*9.8/18*0.04 =2.04*10^5
B.
similarly this question has also the same steps...
C.
here the new surface area will b 14*0.04 m^2...as 4 tires are raised...
so again stress will b =weight/new area.
in the first question, stress is simply the pressure exerted by the truck on the road...
so stress will b = force (in this case weight=m*g)/total area(18*0.04)
P=15*10^3*9.8/18*0.04 =2.04*10^5
B.
similarly this question has also the same steps...
C.
here the new surface area will b 14*0.04 m^2...as 4 tires are raised...
so again stress will b =weight/new area.