A 2kg box is pushed 3m up a 30degree incline at constant velocity by a 20N force directed along the surface of the incline with a coefficient of kinetic friction of 0.6. What net work is done on the box? How much work is done by pushing force? By friction force? By normal force?
College physics...please help!!
College physics...please help!!
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work is done by pushing force
= 20*3
= 60 J --answer
frictional force = 2 * 9.81 * cos 30 * 0.6
=10.19 N
work done by friction
= 10.19 * 3
= 30.57 J --answer
work done by normal force
= 2 * 9.81 * cos 30 * 0
= 0 --answer
net work is done on the box
= ptential energy gained + friction work done
= 2 * 9.81 * 3 * sin 30 + 30.57
= 6 J ---answer
= 20*3
= 60 J --answer
frictional force = 2 * 9.81 * cos 30 * 0.6
=10.19 N
work done by friction
= 10.19 * 3
= 30.57 J --answer
work done by normal force
= 2 * 9.81 * cos 30 * 0
= 0 --answer
net work is done on the box
= ptential energy gained + friction work done
= 2 * 9.81 * 3 * sin 30 + 30.57
= 6 J ---answer