Define g(x) = Integral f (t) dt ( integrated between 0 to x) then
1. g is monotone and bounded
2. g is monotone but not bounded
3. g is bounded but not monotone
4. g is neither monotone nor bounded
1. g is monotone and bounded
2. g is monotone but not bounded
3. g is bounded but not monotone
4. g is neither monotone nor bounded
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If f(x) is continous on[0,1]
then f is bounded on [0,1]
which implies g is bounded on [0,1].
Since f>=0 on [0,1], g(x) as defined
is a monotone increasing function of x.
This follows directly from a basic property
of the Rieman integral:
if 0<=x
int{f(t)|t=0 to y}=int{f(t)|t=0 to x}
+int{f(t)|t=x to y}>=int{f(t)|t=0 to x}.
So the answer is 1.
then f is bounded on [0,1]
which implies g is bounded on [0,1].
Since f>=0 on [0,1], g(x) as defined
is a monotone increasing function of x.
This follows directly from a basic property
of the Rieman integral:
if 0<=x
+int{f(t)|t=x to y}>=int{f(t)|t=0 to x}.
So the answer is 1.