Hi! Thank you so much for looking :).
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[H+] = 10^(-pH) = 10^(-3)
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your log10 is used to go the other way
pH = -log10([H+])
to confirm in case in point
pH = -log10(10^-3) = - - 3 = 3 check
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your log10 is used to go the other way
pH = -log10([H+])
to confirm in case in point
pH = -log10(10^-3) = - - 3 = 3 check