F(x) = 2x^5 -3x^4 + x^3 - 6x + 20: x = 2
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F(x) = 2x^5 -3x^4 + x^3 - 6x + 20: x = 2

[From: ] [author: ] [Date: 11-06-14] [Hit: ]
d.2*2^5-3*2^4+2^3-6*2+20=32so, it is a-10-itll be a.32,funny question!!......
evaluate

a.32
b.10
c.8
d.4

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Just plug in the 2 on all x and solve it :)


32 is the answer

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just plug in 2 wherever you see x and solve

2*2^5-3*2^4+2^3-6*2+20=32
so, it is a

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10

-
it'll be a.32,funny question!!
1
keywords: 20,F(x) = 2x^5 -3x^4 + x^3 - 6x + 20: x = 2
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