Here's the formula: H2C2O4 (aq) + 2KOH (s) ---> K2C204 (aq) + 2H20 (l)
Any help would be immensely appreciated. :)
Any help would be immensely appreciated. :)
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H2C2O4 + 2 KOH → K2C2O4 + 2 H2O
(1.15 g KOH) / (56.1057 g/mol) x (1/2) / (0.200 mol/L) = 0.05124 L = 51.2 mL
(1.15 g KOH) / (56.1057 g/mol) x (1/2) / (0.200 mol/L) = 0.05124 L = 51.2 mL