What volume of 0.200 M H2C2O4 is required to react completely with 1.15 g of KOH
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What volume of 0.200 M H2C2O4 is required to react completely with 1.15 g of KOH

[From: ] [author: ] [Date: 11-06-13] [Hit: ]
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Here's the formula: H2C2O4 (aq) + 2KOH (s) ---> K2C204 (aq) + 2H20 (l)

Any help would be immensely appreciated. :)

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H2C2O4 + 2 KOH → K2C2O4 + 2 H2O

(1.15 g KOH) / (56.1057 g/mol) x (1/2) / (0.200 mol/L) = 0.05124 L = 51.2 mL
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