A 613kg mass is placed on a forklift that can generate 950W of power. What is the constant speed of the forklift while lifting this load?
Its simple enough, I just can't figure it out. Thanks guys!
Its simple enough, I just can't figure it out. Thanks guys!
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(613 x 9.8) = weight of 6,007.4N. If this load was lifted, say1m., work done = (6,007.4 x 1) = 6,007.4 joules.
1 joule = 1W/sec., so with 950W., you would use 950 joules in 1 second max.
(950/6,007.4) = 0.158m., or 1.58cm/sec., constant lift speed.
1 joule = 1W/sec., so with 950W., you would use 950 joules in 1 second max.
(950/6,007.4) = 0.158m., or 1.58cm/sec., constant lift speed.
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I'll take a shot at this... but idk if my answer will be right.
Well power is just Joules/second. So plug in 950 J into K=1/2mv^2, the equation for kinetic energy.
Solve for v... v = sqr rt of 2k/m
Plug in.... v = sqr rt of 2(950 J)/ 613 kg
v= 1.76 m/s
once again idk my physics may be off. do you have the answer with you?
EDIT: lol oh okay sorry. i think the guy below figured it out though :D
Well power is just Joules/second. So plug in 950 J into K=1/2mv^2, the equation for kinetic energy.
Solve for v... v = sqr rt of 2k/m
Plug in.... v = sqr rt of 2(950 J)/ 613 kg
v= 1.76 m/s
once again idk my physics may be off. do you have the answer with you?
EDIT: lol oh okay sorry. i think the guy below figured it out though :D