1) John and two friends rent a canoe at a park. Each person must rent a life jacket. If the bill for the rental of the canoe and life jackets is $41, for how many hours did they rent the canoe? ($5.00
Because i thought all rational numbers can be put in the form of A over B?-The previous poster is correct, 4.1 can be thought of as 41/10, but a way I was taught that I find simpler:
Irrational numbe
Find the average value of the function f(x,y)= xy over the rectangle 0 -Since the area of the rectangle is 2 * 3 = 6, the average value equals
(1/6) * ∫(x = 0 to 2) ∫(y = 0 to 3) xy dy dx
= (1/6) * ∫(
I dont quite understand this fraction thing on a number line, like how do you know where it goes, can someone explain this to me, I have tried looking for a fraction number line on google, but cant fi
Show that for any quadratic function of the from y=a(x-p)(x-q), the tangents at the x-intercepts always intersect at the axis of symmetry. (Answer: x = (p + q) / 2)-I answered a question very similar
Have a tricky one here...?
Integral of sec^3x*tan^2x dx
I can get part way thorough it, but can never get the right answer.
Thanks-For the sake of adopting a reasonably efficient shorthand, let t =
Eg:
There is a raffle with 10 tickets, you buy 1 ticket, you have a 10% chance of winning
If there is another raffle with the same odds (you have a 10% chance to win)
What is the chance that you wi
The velocity function is v(t) =t2−5t +6 for
a particle moving along a line. Find the displacement
(net distance covered) of the particle during the time
interval [-2,5].
displacement =???-v(t) =t2−5t
Find the values of the trigonometric functions of t if sec t= 6/4, and the terminal point of t is in quadrent IV.
I am given a chart with blanks for sin t, cos t, tan t, and cot t. It asks for non de
The Question is: solve giving values of X from 0 to 360 degrees inclusive
2tan(X/2) + 3tan(X) = 0
Ive tried everything i can think of but nothing seems to work, please explain how you got the answer
10 points for the best answer!-y = (1/2)ln(x³ + 4)
use chain rule
y = (1/2)*1/(x³ + 4) * 3x²
y = 3x²/(2x³ + 8)-y = 1/2 * ln(x^3 + 4)
Put the 1/2 on the outside and just focus on d/dx (ln(x^3 + 4))
B
Find the maximum rate of change of f at the given point and the direction in which it occurs.
f(x, y, z) = (8x + 4y)/z, (20, 8, -4)
So I got But I got it wrong!-f(x,y,z) = (8x + 4y) / z = 8x/z + 4y
Find the points P and Q which are as close as possible.
P lies on (-3t, 2 - 4t, -3 + 6t).
Q lies on (-21, 29 - 3t, 27 + 6t).
Please use vectors, dot products, cross products, and the like for this p
That would be great if you could show the steps. Thanks! :D-Note that since e^(-x) = 1/e^x, we have:
e^x - 1/e^x = 1.
Now, let u = e^x. Applying this substitution gives:
u - 1/u = 1.
Multiplying bot
