I have to solve the following equation,
a. Integral if (x)/ (1 + x^4) dx
b. Integral from 1/6 to 1/2 of (csc (pi*t) * cot (pi*t)) dt
I have to do u- substitution and we have not covered this in cl
Positive because for any number n:
(n*n) and (-n)*(-n) is always positive hence (a-1)^2 is always positives.
Then the square root sign as written always refers to the positive square root of a numbe
Can anyone prove this identity for me?I will really appreciate it.-Use
sec^2A-tan^2A=1
take the numerator
secA+tanA-1=
secA+tanA-(sec^2A-tan^2A)=(secA+tanA)-…
now take (secA+tanA) as common
=(secA+tan
Explain why no real numbers is a solution to the equation x+4=x+2
solve -41 ≤ 9x+ 13≤ 53 and graph the solution on a number line
sorry i dont have a graph to show u guys but it says
Use the graph b
Ive gone through it several times and havent been able to come out with the correct derivative, or its equivalent. The actual derivative by derivative rules is 2 - 3/x^2-I always hated these; if I cou
Show the work to solve |3x - 2|
Describe the graph of the solution in words.
if you guys cant solve it it would help allot if you could just describe the graph of the solution in words. thanks :]-
I think its quite weird, but I dont know. Is it just me? I think it may be my teacher, she makes it seem extremely hard, but when I do regular Algebra in my extra class, its so fun for me, and I reall
y=3+8x-6(squareroot x)/x-First simplify 6sqrt(x)/x to 6x^(.5)*x^(-1) = 6x^(-1/2)
y = 3 + 8x - 6x^(-1/2)
dy/dx = 8 + 3x^(-3/2)
Jen-Best way to deal with root derivatives is to change it to whatever
How do I divide an equilateral triangle into 6,7 and 8 other equilateral triangles. Please help.... How do I divide it into 6,7 or 8 other equilateral triangles. I really dont have much time to answer
The acceleration vector is a(t)=−4cos2t_i + −4sin2t_j + 1t_k
The initial velocity is v(0)=i+k , and
The initial position vector is r(0)=i+j+k
Compute v(t) and r(t).-v(t) = antiderivative of accelera
be specific-1000 (1.08)^n = 2500
Divide both sides by 1000:
(1.08)^n = 2.5
Take natural log of both sides, then solve for n:
ln(1.08^n) = ln(2.5)
n ln(1.08) = ln(2.5)
n = ln(2.5) / ln(1.08)
n = 11.
http://www.wolframalpha.com/input/?i=int…
thats the answer but I want to know the steps on how to do it, I heard substitution works but I dont know how. 10 points fast :)-∫ x/√(x+3) dx
let u = x + 3
Find the points P and Q which are as close as possible.
P lies on (-3t, 2 - 4t, -3 + 6t).
Q lies on (-21, 29 - 3t, 27 + 6t).
Please use vectors, dot products, cross products, and the like for this p