When given the equation A=1000(1.08)^n, how would I solve for n when A is 2500? without using a graph.

be specific

1000 (1.08)^n = 2500

Divide both sides by 1000:
(1.08)^n = 2.5

Take natural log of both sides, then solve for n:
ln(1.08^n) = ln(2.5)
n ln(1.08) = ln(2.5)
n = ln(2.5) / ln(1.08)

n = 11.905903537

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Check: 1000 * 1.08^(11.905903537) = 2499.9999999992

ok

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