The polar equation is:
r = 5 / (1+cosθ)
The options are:
A.
x^2 = 25y - 10
B.
x^2 = 10 - 25y
C.
y^2 = 25x - 10
D.
y^2 = 10 - 25x
Or something very similar to those options. (Im doing this from
if three of the cards have the same face value and the other two have different face values?
So far i have this for a solution
(13C1) * (4C3) * (12C1) * (4C1) * (11C1) * (4C1)
Where xCy is a combin
Please help me with this problem.. i couldnt even get anything nearer to it.-To Prove : cosֿ¹ x = 2 · sinֿ¹ √[ ( 1 - x ) / 2 ].
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On the RHS,
let : x = cos 2Φ.
∴ 2Φ
1. Find the work done (in Joules) in pushing a car a distance of 8 meters while exerting a constant force of 900 N.
2. A heavy rope, 50 ft long, weighs 0.5 lb/ft and hangs over the edge of a building
If m, n & p, q is full positive number . Then m^2 - n^2 = p^3 & m^3 - n^3 = q^2 . Find the smallest m & n .-m=6
n=5
p=3
q=9-Impressive ! ? i say nay...Report Abuse
I need to find the answer to an exponential growth formula with the formula Qt=Qo(b)^t
where Qt=quantity after time t, Qo is the original quantity and b= the growth rate
I need to work out t where Qt
1 + 2/(1*2*3) + 3/(1*2*3*4*5) + ...
I just need help finding the S_n part... I know that the numerator will be n but I dont understand how to get the denominator with all of these ! (whatever theyre
Please feel free to point out anywhere I have erred in this question as that is the way I will learn more.
I recently stumbled upon a question on yahoo answers that said, A cruise ship sails with a to
lim
x--> - infinity (x^3 + e^-x)-Lim x-> -∞ [x^3 + 1/e^x]
If we naively sub in -∞, we get:
L = (-∞)^3 + 1/e^(-∞)
L = (-∞)^3 + e^(∞)
Now (-∞)^3 = -∞ and e^(∞) = ∞, thus the question is basically jus
title says all-r=r^3+2
so
r^3-r+2=0
and look for the real root.
Chart it around r=0
r =-2 -1 0 1 2
lhs =-4 2 2 2 8
Real root between r=-2 and r=-1-I would like to apologize to peabody for not re
A grab bag contains 3 football cards and 7 basketball cards. An experiment consists of taking one out of the bag, replacing it, and then selecting another card. What is the probability of selecting a
I just cannot get past the first part of this problem. Any help would be awesome!
Problem: Consider the following recurrence relation:
an = 6a(n-1) - 9a(n-2) + 2^n . a0 = 1, a1 = 6. Of course all the
