A grab bag contains 3 football cards and 7 basketball cards. An experiment consists of taking one out of the bag, replacing it, and then selecting another card. What is the probability of selecting a football card and then a basketball card? Express answer as a decimal.
Thank you!
Thank you!
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There are 10 cards in all.
3/10 * 7/10
21/100
0.21 <===ANSWER
3/10 * 7/10
21/100
0.21 <===ANSWER
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the probability of selecting a football card and then a basketball card
is
the possibility of drawing a football card is
3/10
and after it has been replaced the possibility of drwing basketball card is 7/10
thus the the probability of selecting a football card and then a basketball card is
= 3*7/100
=21/100
=0.21
thats it:)
is
the possibility of drawing a football card is
3/10
and after it has been replaced the possibility of drwing basketball card is 7/10
thus the the probability of selecting a football card and then a basketball card is
= 3*7/100
=21/100
=0.21
thats it:)
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0.3 for football 0.7 for baseball