Math?????? Help me??

I have to put this equation into a chart: y= -3(x+2).

How would I put it in a chart?

X-------Y
?-------?
?-------?
?-------?

a) -2 0
-1 -3
0 -6

b) -2 0
-1 3
0 6

c) -2 6
-1 3
0 0

d) -2 0
-1 1
0 2

You sub in values for x, note that down, then note down what you get out as y

so starting with -2..

-3(-2+2) = 0 so -2,0 is the first value, so it is not c)

-3(-1+2) = -3 so -1, -3 is the second value, the answer then must be a)

We can check by doing the last one...

-3(0+2) = -6

are you sure you have copied the problem correctly?

y= -3(x+2).

X-------Y
?-------?
?-------?
?-------?


if x = -2
y = -3(x + 2)

y = -3( -2 + 2) = -3(0) = 0

so C is out.

if x = -1
y = -3(x + 2)

y = -3( -1 + 2) = -3(1) = -3

so B and D are out too.
You know the answer is A now, but you can check

if x = 0
y = -3(0 + 2)

y = -3(2) = -6

And A is confirmed as the answer.

ANS: a)
select a value for x and find the corresponding value of y:
Ex: if x = -2 then
y = -3(x+2) = -3(-2+2) = 0
So, if x = -2 then y = 0

Likewise:
x y
-2 0
-1 -3
0 -6

ANS: a)