Hi,
Can you please help me and tell me if I got the right answers in these problems? :
http://i49.tinypic.com/2nsugr7.jpg
I just need the integral (I don't have to integrate).
Thank you in advance!
Can you please help me and tell me if I got the right answers in these problems? :
http://i49.tinypic.com/2nsugr7.jpg
I just need the integral (I don't have to integrate).
Thank you in advance!
-
I think you did everything correct.
a)
y = x² + 1 <==> x = √(y - 1)
y(2) = x² + 1 = 5
length = 2π*radius = 2πy
height = 2 - x = 2 - √(y - 1)
thickness = Δy
from y = 1 to y = 5
V = ∫ 2πy(2 - √(y - 1) ) dy
or
V = ∫ 4πy - 2πy√(y - 1) dy
b)
length = 2π*radius = 2π(y - 1)
height = 2 - x = 2 - √(y - 1)
thickness = Δy
V = ∫ 2π(y - 1)(2 - √(y - 1) ) dy
or
V = ∫4πy - 4π + 2π√(y - 1) - 2πy√(y - 1) dy
c)
length = 2π*radius = 2πx
height = y - 1 = x²
thickness = Δx
from x = 0 to x = 2
V = ∫ 2πx(x²) dx
V = ∫ 2πx³ dx
d)
length = 2π*radius = 2π(4 - x)
height = y - 1 = x²
thickness = Δx
from x = 0 to x = 2
V = ∫ 2π(4 - x)(x²) dx
or
V = ∫ 8πx² - 2πx³ dx
a)
y = x² + 1 <==> x = √(y - 1)
y(2) = x² + 1 = 5
length = 2π*radius = 2πy
height = 2 - x = 2 - √(y - 1)
thickness = Δy
from y = 1 to y = 5
V = ∫ 2πy(2 - √(y - 1) ) dy
or
V = ∫ 4πy - 2πy√(y - 1) dy
b)
length = 2π*radius = 2π(y - 1)
height = 2 - x = 2 - √(y - 1)
thickness = Δy
V = ∫ 2π(y - 1)(2 - √(y - 1) ) dy
or
V = ∫4πy - 4π + 2π√(y - 1) - 2πy√(y - 1) dy
c)
length = 2π*radius = 2πx
height = y - 1 = x²
thickness = Δx
from x = 0 to x = 2
V = ∫ 2πx(x²) dx
V = ∫ 2πx³ dx
d)
length = 2π*radius = 2π(4 - x)
height = y - 1 = x²
thickness = Δx
from x = 0 to x = 2
V = ∫ 2π(4 - x)(x²) dx
or
V = ∫ 8πx² - 2πx³ dx