How to find the slope of the line that passes through (1,3) and (3,-3)

First label your variables, so lets say:

(1, 3) :
x1 = 1
y1 = 3

(3, -3):
x2 = 3
y2 = -3

Then simply use the slope formula given in your previous question:

m = y2 - y1 / x2 - x1

Plug in your numbers...

m = (-3 - 3) / (3 - 1)
m = (-6) / (2)
m = -6/2
m = -3

And BAM! the slope is -3.

M (slope) = x(2) - x(1) divided by y(2) - y(1)

Take your two points. (1,3) and (3,-3)

Remember. (x,y)

So x(2) is 3. X(1) is 1. So 3-1 divided by

Y(2) is -3 and y(1) is 3 so -3- 3

Simplify

3-1 is 2

And -3-3 is -6

So 2/-6

M= -1/3 (slope)

m =( -3 - 3) / (3 - 1) = -6 / 2 = -3