Why is this nonlinear

[From: ] [author: ] [Date: 12-09-04] [Hit: ]

.x(d³y/dx³) - (dy/dx)^5 + y = 0-Because the derivative of y is raised to the 5th power(dy/dx)^5-That is a differential equation. Its solution will not be of the form y = mx + c, a linear relationship between x and y. It will not be linear because (dy/dx) is raised to the fifth power and there is also the 3rd. derivative of y with respect to x.......

why is this nonlinear....x(d³y/dx³) - (dy/dx)^5 + y = 0

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Because the derivative of y is raised to the 5th power (dy/dx)^5

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That is a differential equation. Its solution will not be of the form y = mx + c, a linear relationship between x and y. It will not be linear because (dy/dx) is raised to the fifth power and there is also the 3rd. derivative of y with respect to x.

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