I have to determine the open intervals on which the function f(x)=(x/(x^2+1)) is increasing.
The derivative of this function is (1-x^2)/((x^2+1)^2).
So, where do I need to head from here? Thinking I set the derivative equal to 0, and solve for x's. Those x's are the roots of the equation (maxes/mins), so I can pick points between them and plug into the original formula and see if the line between the two maxima/minima is increasing or decreasing. Is this the right way to approach this?
The derivative of this function is (1-x^2)/((x^2+1)^2).
So, where do I need to head from here? Thinking I set the derivative equal to 0, and solve for x's. Those x's are the roots of the equation (maxes/mins), so I can pick points between them and plug into the original formula and see if the line between the two maxima/minima is increasing or decreasing. Is this the right way to approach this?
-
You are on the right track, you set your derivative to zero to find the critical values. Because the denominator would leave you with non-real answers, only worry about the numerator.
(1-x^2)=0
x^2=1
x= -1,1
Also, note that in the original function, x=0 would make f(x)=0, so on the sign chart, the values for the intervals will be -1, 0, and 1.
f ' (x)______-1______0______1______
(x)
Next, we need to plug in a number from each of those intervals into the derivative function to find whether the answer is positive or negative. I will choose -5, -0.5, 0.5, and 5.
I get the values
f '(-5) = -0.35
f '(-.5)= 0.48
f '(.5) = 0.48
f '(5) = -0.35
f ' (x)___-___-1___+___0___+___1___-___
(x)
From those values we can conclude that the graph is increasing on the intervals (-1,0)U(0,1), or simply (-1,1). Hope that helped.
(1-x^2)=0
x^2=1
x= -1,1
Also, note that in the original function, x=0 would make f(x)=0, so on the sign chart, the values for the intervals will be -1, 0, and 1.
f ' (x)______-1______0______1______
(x)
Next, we need to plug in a number from each of those intervals into the derivative function to find whether the answer is positive or negative. I will choose -5, -0.5, 0.5, and 5.
I get the values
f '(-5) = -0.35
f '(-.5)= 0.48
f '(.5) = 0.48
f '(5) = -0.35
f ' (x)___-___-1___+___0___+___1___-___
(x)
From those values we can conclude that the graph is increasing on the intervals (-1,0)U(0,1), or simply (-1,1). Hope that helped.