Solving Rational Inequalities.. i dont get it! help

Hi everyone, i really have no idea how to do these.. i keep getting answers that dont make sense.

1. When the equation 2-(3/b)=(5/(b+2) is solved for b, the solution set is -1 and 3. Explain why the number line must be separated into five segments by the numbers -2,-1,0 and 3 in order to check the solution set of the inequality 2-(3/b)>(5/(b+2).

2. a/4>(a/2)+6

3. |x|/x<0

4. ((y-3)/5)<((y+2)/10)

thanks so much!!

1.) Because the solution set WOULD have been -2,-1,0, and 3, but if you use -2 or 0, you get zero in the denominator of one of the fractions. You can't have a zero denominator.

2.)

a/4 > (a/2) + 6

Multiply everything by 4

a > 2a + 24
-a > 24
a < -24

3.)

|x|/x < 0

x < 0

4.)

(y - 3)/5 < (y + 2)/10

Multiply everything by 10

2(y - 3) < y + 2
2y - 6 < y + 2

y < 8

You're welcome!!