How does the acceleration due to gravity at that location compare to acceleration at the surface of Earth?
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Acceleration due to gravity is inversely proportional to the distance squared.
a = g/f^2
where f = the distance in terms of earth radii
g = acceleration of gravity at the surface of the earth
So at twice the radius, the acceleration would be 1/4.
This comes from g = G*M/r^2
G = constant
M = mass of the earth
r = distance from the center of the earth with r equal or greater than the surface radius
So if we want the acceleration at some other distance f*r then
a = G*M/(f*r)^2 = (1/f^2)*(G*M/r^2) = g/f^2
a = g/f^2
where f = the distance in terms of earth radii
g = acceleration of gravity at the surface of the earth
So at twice the radius, the acceleration would be 1/4.
This comes from g = G*M/r^2
G = constant
M = mass of the earth
r = distance from the center of the earth with r equal or greater than the surface radius
So if we want the acceleration at some other distance f*r then
a = G*M/(f*r)^2 = (1/f^2)*(G*M/r^2) = g/f^2