What is the nth term of 2, -4, 6, -8, 10

what is the nth term for 2, -4, 6, -8, 10
i am not sure
thanks

-2(-1)^n*n

This is an alternating sequence. Alternating sequence always have (-1)^(n). When n becomes odd, the term stays negative. When n becomes event, the term changes to positive. The general sequence for this is:

a_n = 2n * (-1)^(n + 1)

When n = 1 (the first term in the sequence), a_1 = 2(1) * (-1)^(1 + 1) = 2(1) * (-1)^(2) = 2 * 1 = 2
When n = 2 (the second term in the sequence), a_2 = 2(2) * (-1)^(2 + 1) = 2(2) * (-1)^(3) = 4 * -1 = -4
When n = 3 (the third term in the sequence), a_3 = 2(3) * (-1)^(3 + 1) = 2(3) * (-1)^(4) = 6 * 1 = 6

You should see the pattern there.

nth term=a+(n-1)d
In this case, a=2 and d=-6
So
=2+6n-6
=6n-4
I guess this is the answer
Regards
Aftab

t(n) = (2n)(-1)^(n-1)