x^1/6 times x^2/3
It is hard to write my problem because I don't know how to make a radicand symbol on here, but the index of the first ik is 6, and the second index is 3 then x raised to the 2nd...
It is hard to write my problem because I don't know how to make a radicand symbol on here, but the index of the first ik is 6, and the second index is 3 then x raised to the 2nd...
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it seems simple just add 1/6 to 2/3 and then you have 1/9 so i think x^1/9
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To simplify this problem, remember that when multiplying two numbers of the same base, you can simply add the exponents:
x^(1/6) * x^(2/3) = x^(1/6 + 2/3)
1/6 + 2/3 = 5/6, so the answer is x^(5/6), or the sixth root of x^5
x^(1/6) * x^(2/3) = x^(1/6 + 2/3)
1/6 + 2/3 = 5/6, so the answer is x^(5/6), or the sixth root of x^5
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The power rule is:
x^q * x^p= x^(p+q)
For your problem we have
q=1/6 and p=2/3
q+p=1/6+2/3=1/6+4/6=5/6
which leads to
x^1/6 * x^2/3 = x^5/6
x^q * x^p= x^(p+q)
For your problem we have
q=1/6 and p=2/3
q+p=1/6+2/3=1/6+4/6=5/6
which leads to
x^1/6 * x^2/3 = x^5/6