How do you solve this quadratic system

[From: ] [author: ] [Date: 11-11-26] [Hit: ]

y= 2x^2-12x+16
y= x^2+2x+3

y= 2x^2-12x+16
y= x^2+2x+3

2x²-12x+16 = y = x²+2x+3
x²-14x+13 = 0
(x-1)(x-13) = 0
x = 1, 13
y = 6, 198

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