4a²= 9a+9
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4a²-9a-9= 0
factoring isn't all that easy owing to the 4 in the second order term but the 9's indicate we're looking at a 4a term and a 3.
(4a+3)(a-3) looks good, let's multiply it out and check: 4a^2 - 12a + 3a - 9 yes that works.
therefore either 4a+3 = 0 or a-3 = 0
therefore a = -3/4 or a = 3
hope this helps.
factoring isn't all that easy owing to the 4 in the second order term but the 9's indicate we're looking at a 4a term and a 3.
(4a+3)(a-3) looks good, let's multiply it out and check: 4a^2 - 12a + 3a - 9 yes that works.
therefore either 4a+3 = 0 or a-3 = 0
therefore a = -3/4 or a = 3
hope this helps.
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I would subtract 9a + 9 on both sides, leaving you with 4a^2 - 9a - 9 = 0
It factors to (4a + 3)(a - 3) = 0
So then you can set up two possible equations:
4a + 3 = 0 and a - 3 = 0. Solve for a in both and you will get a = -4/3, 3. You should check to make sure neither are extraneous. You can do this by plugging them into the original equation you had.
It factors to (4a + 3)(a - 3) = 0
So then you can set up two possible equations:
4a + 3 = 0 and a - 3 = 0. Solve for a in both and you will get a = -4/3, 3. You should check to make sure neither are extraneous. You can do this by plugging them into the original equation you had.
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4a²= 9a+9
4a^2 - 9a - 9 = 0
(4a + 3)(a - 3)
4a^2 - 9a - 9 = 0
(4a + 3)(a - 3)