How do I solve the quadratic equation
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How do I solve the quadratic equation

[From: ] [author: ] [Date: 11-11-27] [Hit: ]
You should check to make sure neither are extraneous. You can do this by plugging them into the original equation you had.......
4a²= 9a+9

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4a²-9a-9= 0
factoring isn't all that easy owing to the 4 in the second order term but the 9's indicate we're looking at a 4a term and a 3.

(4a+3)(a-3) looks good, let's multiply it out and check: 4a^2 - 12a + 3a - 9 yes that works.

therefore either 4a+3 = 0 or a-3 = 0

therefore a = -3/4 or a = 3

hope this helps.

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I would subtract 9a + 9 on both sides, leaving you with 4a^2 - 9a - 9 = 0
It factors to (4a + 3)(a - 3) = 0
So then you can set up two possible equations:
4a + 3 = 0 and a - 3 = 0. Solve for a in both and you will get a = -4/3, 3. You should check to make sure neither are extraneous. You can do this by plugging them into the original equation you had.

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4a²= 9a+9

4a^2 - 9a - 9 = 0

(4a + 3)(a - 3)
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