A steel ball with a constant velocity of 0.800 m/s rolls off the edge of a table. The table is 0.950 meter high. How far from the edge of the table does the ball land?
The last part of this question confuses me. Please help!
The last part of this question confuses me. Please help!
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What you have to remember is that the horizontal velocity of the ball doesn't change when it's falling.
Vertical and horizontal speed don't depend on each other.
So we just need the time that elapses while the ball is falling to calculate the distance it travels in horizontal direction.
h=0.5gt²
=>t=√(h/0.5g)=√(0.950/(0.5*9.80))=0.44… s
x=v*t=0.800*0.440315=0.352252 m is the horizontal distance between the edge of the table and the place where the ball lands
Vertical and horizontal speed don't depend on each other.
So we just need the time that elapses while the ball is falling to calculate the distance it travels in horizontal direction.
h=0.5gt²
=>t=√(h/0.5g)=√(0.950/(0.5*9.80))=0.44… s
x=v*t=0.800*0.440315=0.352252 m is the horizontal distance between the edge of the table and the place where the ball lands