Antiderivative/ Integral help

1)Find antiderivative for ∫ex(3ex + 1)-1/3 dx =
2)Calculate integral of
1.86
∫ sin (4.3 x) dx =
0.52
3)Find integral
2.75
∫ (2.73x2 - 8.41x + 7) dx =
0.5

1)
∫ex(3ex + 1)-1/3 dx = ∫(3e^2x +e^x -1/3) dx

= 3e^2x /2 + e^x -(1/3) x + C

2)
∫ sin (4.3 x) dx = -cos(4.3 x) /4.3 = (-1/4.3) cos(4.3x)

Let F(x) = (-1/4.3) cos(4.3x)
F(1.86)-F(0.52) =.033377 -.143539
=-0.110162

3)
2.75
∫ (2.73x2 - 8.41x + 7) dx = 2.73 x^3 /3 -8.41 x^2/2 +7x
0.5

Let F(x) = 2.73 x^3 /3 -8.41 x^2/2 +7x
F(2.75)-F(.5) = 6.37484 -2.5625
=3.81234