Can someone explain what i need to do for
this equation please
http://i.imgur.com/YWhER.png
this equation please
http://i.imgur.com/YWhER.png
-
You need to set up a pair of equations with two unknowns x and y
the first equation is given as area
A = xy
6000 = xy
The other equation is for the perimeter
this will be adding up all the sides less the amount cleared by the building
x + (x-10) + y + (y-10) = 334
simplifies to
2x + 2y -20 = 334
or
2x + 2y = 354
divide by 2
x + y = 177
This gives you two equations and two unknowns which you may solve on your own. If this is also an unknown area, I have solved it below
if you solve this second equation for y
x = 177 - y
now substitute this x into the other equation
6000 = xy
6000 = y(177 - y)
6000 = 177y - y^2
or
y^2 - 177y + 6000 = 0
using the quadratic equations
y = (177 +_sqrt (177^2 -4(1)(6000)) / 2(1)
y = 177 +_85.61 / 2
y = 131.3 or y = 45.7
a little checking will reveal that these two numbers are our x and y dimensions and can be interchanged without violating any of the conditions of the problem
the first equation is given as area
A = xy
6000 = xy
The other equation is for the perimeter
this will be adding up all the sides less the amount cleared by the building
x + (x-10) + y + (y-10) = 334
simplifies to
2x + 2y -20 = 334
or
2x + 2y = 354
divide by 2
x + y = 177
This gives you two equations and two unknowns which you may solve on your own. If this is also an unknown area, I have solved it below
if you solve this second equation for y
x = 177 - y
now substitute this x into the other equation
6000 = xy
6000 = y(177 - y)
6000 = 177y - y^2
or
y^2 - 177y + 6000 = 0
using the quadratic equations
y = (177 +_sqrt (177^2 -4(1)(6000)) / 2(1)
y = 177 +_85.61 / 2
y = 131.3 or y = 45.7
a little checking will reveal that these two numbers are our x and y dimensions and can be interchanged without violating any of the conditions of the problem