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[From: ] [author: ] [Date: 11-11-08] [Hit: ]
......
y = ax - 2a² and x = 2 + 3a

Express y in tems of a
Evaluate y when a = -2

-
y = ax - 2a^2
y = a(2+3a) - 2a^2
y = 2a + 3a^2 - 2a^2
y = 2a + a^2
y = 2(-2) + (-2)^2
y = -4 + 4
y = 0

-
y = ax - 2a²
and
x = 2 + 3a

Express y in tems of a
Evaluate y when a = -2

substitute for x:

y = a(2 + 3a) - 2a^2

expand and simplify...

y = 2a + 3a^2 - 2a^2 = 2a + a^2 = a(a + 2)

evaluate: y = - 2(0) = 0

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