I know I can just use my graphing calculator to graph this equation. First I need to solve for y and I get y = x²/16 and put it into the calculator. But I would like to find the focus, directrix and focal diameter first.
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y = (1/16)x²
vertex (0, 0)
a = 1/16
a is positive so the parabola opens upwards
p = 1/(4a) = 4
focus (0, 4)
directrix y = -4
focal parabola = 2a = 1/8
vertex (0, 0)
a = 1/16
a is positive so the parabola opens upwards
p = 1/(4a) = 4
focus (0, 4)
directrix y = -4
focal parabola = 2a = 1/8