Use the given zero to find all the zeros of the function.
Function: h(x) = -x^3 +2x^2 - 16x +32
Zero: -4i
Function: h(x) = -x^3 +2x^2 - 16x +32
Zero: -4i
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Well, imaginary zeros come in pairs so another zero is positive 4i. The most number of roots you can have is 3 because of the degree of the polynomial which is 3. Because you already have 2, you can use either synthetic or long division to depress the equation. In other terms, you have 4i and -4i as two of your zeros, so that would make the factors, (x+4i)(x-4i). However, you need to have that third factor to make -x^3+2x^2-16x+32.
To look at synthetic division: http://www.purplemath.com/modules/synthd…
To look at long division: http://www.purplemath.com/modules/polydi…
Make sure to divide (x+4i) by -x^3 +2x^2 - 16x +32, and then divide the quotient from (x-4i)!
Once you have divided, you should be left with a depressed equation in which you can set to 0, and then solve for x.
To look at synthetic division: http://www.purplemath.com/modules/synthd…
To look at long division: http://www.purplemath.com/modules/polydi…
Make sure to divide (x+4i) by -x^3 +2x^2 - 16x +32, and then divide the quotient from (x-4i)!
Once you have divided, you should be left with a depressed equation in which you can set to 0, and then solve for x.
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Thats hard but :
solve each side then subtract
solve each side then subtract