At equilibrium in the following reaction at 319 K, the concentration of NO2 (g) is 2.09 M. What is the concentration of N2O4 (g) if the equilbrium constant for this reaction is determined to be 39.68 at 319K?
2 NO2 (g) ↔ N2O4 (g)
THANKS!!!!
2 NO2 (g) ↔ N2O4 (g)
THANKS!!!!
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2 NO2 (g) ↔ N2O4 (g)
K = [N2O4] / [NO2]^2
39.68 = [X] / [2.09]^2
X = 173 M
K = [N2O4] / [NO2]^2
39.68 = [X] / [2.09]^2
X = 173 M