A sample of an ideal gas has a volume of 3.50L at 10.40 Celsius and 1.60atm.

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A sample of an ideal gas has a volume of 3.50L at 10.40 Celsius and 1.60atm.

[From: ] [author: ] [Date: 11-11-08] [Hit: ]

T1 (must be in Kelvin = 10.40 deg C + 273.15) = 283.P2 = 0.V2 = ?T2 = 291.......

What is the volume of the gas at 18.40 Celsius and 0.991 atm. What is the volume of the gas in Liters?

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Use the combined gas equation

P1V1 / T1 = P2V2 / T2

P1 = 1.60 atm
V1 = 3.50 L
T1 (must be in Kelvin = 10.40 deg C + 273.15) = 283.55 K
P2 = 0.991 atm
V2 = ? L
T2 = 291.55 K

Solve for V2
V2 = P1V1T2 / P2T1
= 1.60 atm x 3.50 L x 291.55 K / (0.991 atm x 283.55 K)
= 5.81 L (3 sig figs)

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