I need help with a question finding the absolute max and the absolute min values of f

Q: Find the absolute maximum and absolute minimum values of f on the interval [0,3].

f(x) = (x) / (x^2 - x + 1)

Can someone explain how to answer this?

diff(x/(x^2 - x + 1), x) = 1/(x^2 - x + 1) - x*(2*x - 1)/(x^2 - x + 1)^2

solve(1/(x^2 - x + 1) - x*(2*x - 1)/(x^2 - x + 1)^2 = 0)

x1 = - 1, x2 = 1

Choose x = 1, for the restriction to the domain.

f(x) = (x)/(x^2 - x + 1)

f(1) = 1

point (1, 1) = Maximum

f(0) = 0

point (0, 0) = Minimum

you plug it in your calculator and then set your window so the x max is 3 and x min is 0. then you find the highest and lowest point, the absolute max and min respectivly