The perimeter of a rectangle is 30 ft. the length is 11ft longer than the width. let x be the length and y be the width. Write the system of two linear equations. don't solve
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Define variables
l =length, w = width
Perimeter = 2(l = w)
EQUATION (1)
2(l - w) = 30
Length is 11 feet longer than the width
EQUATION (2)
l = w + 11
l =length, w = width
Perimeter = 2(l = w)
EQUATION (1)
2(l - w) = 30
Length is 11 feet longer than the width
EQUATION (2)
l = w + 11
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2W+2L=30=Perimeter
W-11=L
L+11=W
2(L+11)+2L=30
2L+22+2L=30
4L+22=30
4L=52
L=52/4
L=13
W=2
W-11=L
L+11=W
2(L+11)+2L=30
2L+22+2L=30
4L+22=30
4L=52
L=52/4
L=13
W=2