Differentiate this correctly d=2.4+ 0.75x and I give you a best answer rating

or even better can you also differentiate these two thanks.
Im stuck on my homework and im really dumb :D

b) d= 0.2x (x-0.51)
c)d=0.2x (x-5) (x-9.1)

Thanks heaps

Use this formula to solve derivatives
If y = a(x^b)

Then dy/dx = b*a [x^(b-1)]
"a" is a constant. The derivative of a constant BY ITSELF with respect to "x" is always zero.

a) d = 2.4 + 0.75x

d(d)/dx = d(2.4)/dx + d(0.75x)/dx
Apply the derivative to each value in the equation. Note that taking the derivative of a constant is zero, therefore d(2.4)/dx cancels out. And the derivative of 0.74x with respect to x is just 0.75 because dx/dx = 1. So the answer:
d(d)/dx = 0.75

b) d = 0.2x(x-0.51)
Expand the equation using the distributive property.

d = 0.2x^2 - 0.2(0.51)x

Apply the derivative

d(d)/dx = d(0.2x^2)/dx - d(0.2*0.51*x)

Note that 0.2 is a constant, but we don't cancel this out because the constant is not "by itself" (meaning that x^2 is included in the term). You can take this constant out of the derivative and derive d(x^2)/dx, which is 2x. The last part is derived to 0.2*0.51. And so your answer is:
d(d)/dx = 0.4x - 0.102

c) d=0.2x(x-5)(x-9.1)
Expand algebraically. This gets a little difficult, but just work it out step by step and you should be fine. Multiply parts in brackets first:
d= [0.2x(x-5)] (x-9.1)
d= [0.2x^2 - x] (x-9.1)
Then finally multiply the next part.
d=(0.2x^2-x)(x-9.1) USE DISTRIBUTIVE PROPERTY
d=0.2x^3 - 9.1*0.2x^2 - x^2 + 9.1x SIMPLIFY
d = 0.2x^3 - 2.82x^2 + 9.1x NOW Derive

d(d)/dx = d(0.2x^3)/dx - d(2.82x^2)/dx + d(9.1x)/dx
First part derives to 3*0.2x^2. Second term derives to 2*2.82x. Third term: 9.1
So the derivative of d with respect to x is:

d(d)/dx = 0.6x^2 - 5.64x +9.1


Calculus can seem daunting and intimidating. But just remember, if you think about each problem logically and break everything down into steps, you can arrive at the correct answer on your own.

A. 2.4+.75x= .75

B. 0.2x(x-.51)-> .2x^2-.102x-> .4x-.102

C. (.2x)*(x-5)= .2x^2-.1x->(.2x^2-.1x)(x-9.1)= .2x^3-1.82x^2-.1x^2+.91x-> .6x^2-3.64x-.2x+.91

a)d=2.4+ 0.75x
d(2.4)/dx +d(0.75x)/dx
=0+0.75
=0.75

b) d= 0.2x (x-0.51)
=0.2x^2 -0.102x
=d(0.2x^2 -0.102x)/dx
=2*0.2x-1*0.102
=0.4x-0.102

c)d=0.2x (x-5) (x-9.1)

9.1 - 5.64 x + 0.6 x^2

for solving online go to www.wolframalpha.com

c) 0.2 -5^-6 9.1-^10.1?

You wrote it weird and I don't know If I'm right....

For the question it would just be 0.75 cause a number by itself is NOFFIN!