What volume in mL of a 1.43 M solution of NH4Cl (53.49 g/mol) would be required if you wanted 45600 mg of solute?
And can you tell me how to do it too? It's my last problem and I can't seem to find an example in my notes...
And can you tell me how to do it too? It's my last problem and I can't seem to find an example in my notes...
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45600mg(1 mol/53490mg)=0.85 mole NH4Cl
0.85 mole(1000ml/1.43 mole)=594.41ml
0.85 mole(1000ml/1.43 mole)=594.41ml