A given sample of a xenon fluoride compound contains a molecules of type XeF(sub)n, where n is a whole number

a given sample of a xenon fluoride compound contains a molecules of type XeF(sub)n, where n is a whole number Given that 9.03X10 ^20 molecules of XeFn weighs 0.368 detemine that the value of n in the formula

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9.03 x 10^20 molecules XeFn x (1 mole XeFn / 6.02 x 10^23 molecules XeFn) = 0.00150 moles XeFn

0.368 g XeFn / 0.00150 moles XeFn = 245 g/mole XeFn

Since the molar mass of Xe is 131 g/mole, then the Fn part must be 245 - 131 = 114 g/mole.
One F atom has a molar mass of 19.0 g/mole, so 114 / 19.0 = 6 F atoms.

The formula is XeF6.