Algebra help!!! PLEASE!

A passenger train's speed is 60 mph and a freight trains speed is 40 mph. The passenger train travels the same distance in 1.5 hrs less time than the freight train. How long dos it take each train to complete the trip

Note: they both travel the same distance so you gotta get equations linking time with distance for both trains --- Vel = distance / time so time = distance / vel written t = d/v
Let t = Passenger train time

Passenger train : t = d/60 so d = 60t

Freight train : t+ 1.5 = d/40 so d = 40t + 60

so 60t = 40t + 60
so 20t = 60 so t = 3 hrs so Pass Train = 3 hrs and Freight train = 3 +1.5 hrs = 4.5 hrs

Let t = the time it took Train B to travel the distance

Speed( miles/hour) x ( t hours) =

Train A: (60mph) (t-1.5) = distance
Train B: (40mph) (t) = distance

(60)(t-1.5) = (40)(t)
60t-90 = 40t
20t = 90
t = 4.5

Therefore, it takes Train A 3 hours to complete the trip, and Train B takes 4.5 hours.

let it take t min to passenger train

d = 60 t --> (1)

d = 40 (t+1.5)

d = 40t+60 --> (2)

from (1) and (2)

60t = 40t + 60 ==> t = 3

time for passenger train = 3 hours

time for freight train = 4.5 hours

x: hours for the train with 40 mph speed

60(x-1.5)=40.x
20x=90
x=4.5

Train with 60=3 hours
Train with 40=4.5 hours

60 t = 40 ( t + 1.5)
20t = 60
t = 3 hrs
t = 3 + 1.5 = 4.5 hrs

Doesn't the question require a distance?