A flywheel with a radius of 0.700m starts from rest and accelerates with a constant angular acceleration of 0.300 rad/sec^(2).
(a) Compute the magnitude of the resultant acceleration of a point on its rim after it has turned through 60.0 degrees.
(b) Compute the magnitude of the resultant acceleration of a point on its rim after it has turned through 120.0 degrees.
(a) Compute the magnitude of the resultant acceleration of a point on its rim after it has turned through 60.0 degrees.
(b) Compute the magnitude of the resultant acceleration of a point on its rim after it has turned through 120.0 degrees.
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a) 60.0 degrees = 1.047 rad = s
u=0
since it is a constant angular acceleration, the resultant acceleration of a point on its rim after it has turned through 60.0 degrees remain unchanged
v^2 =u^2 + 2as
v^2 = 0 + 2 * 0.3 * 1.047
v = 0.7925 rad/s
angular speed after it has turned through 60.0 degrees.
answer
linear acceleration = 0.7 * 0.3= 0.21 m/s^2
b) since it is a constant angular acceleration, the resultant acceleration of a point on its rim after it has turned through 120.0 degrees remain unchanged.
v^2 =u^2 + 2as
v^2 = 0 + 2 * 0.3 * 2.094
v = 1.12 rad/s
answer
linear acceleration = 0.7 * 0.3= 0.21 m/s^2
u=0
since it is a constant angular acceleration, the resultant acceleration of a point on its rim after it has turned through 60.0 degrees remain unchanged
v^2 =u^2 + 2as
v^2 = 0 + 2 * 0.3 * 1.047
v = 0.7925 rad/s
angular speed after it has turned through 60.0 degrees.
answer
linear acceleration = 0.7 * 0.3= 0.21 m/s^2
b) since it is a constant angular acceleration, the resultant acceleration of a point on its rim after it has turned through 120.0 degrees remain unchanged.
v^2 =u^2 + 2as
v^2 = 0 + 2 * 0.3 * 2.094
v = 1.12 rad/s
answer
linear acceleration = 0.7 * 0.3= 0.21 m/s^2