A simple pendulum has a period of 2.86 s. The acceleration of gravity is 9.8 m/s2 . What is its length?
Answer in units of m
What would its period be on the Moon, where gMoon = 1.67 m/s^2 ?
Answer in units of s
Answer in units of m
What would its period be on the Moon, where gMoon = 1.67 m/s^2 ?
Answer in units of s
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Use the formula T=2pi sqrt(l/g)
2.86=6.28sqrt(l/9.81)
2.86^2=6.28^2(l/9.81)
Continue from there.
2.86=6.28sqrt(l/9.81)
2.86^2=6.28^2(l/9.81)
Continue from there.