Derivative of 5/x^2? 10 points for answer

d/dx (5/x^2)
d/dx (5x^(-2))
(-2)(5)(x^-3)
-10/x^3

f(x) = 5/(x^2) = 5 x^-2

d/dx f(x) = -10 x^-3 = -10/ (x^3)

rule: multiply exponent by constant and place in front, then decrease exponent by 1

... f(x) = 5/x^(2)
or f(x) = 5x^(-2)
or df/dx = -10x^(-3)

d/dx (5/x^2)
d/dx (5x^(-2))
(-2)(5)(x^-3)
-10/x^3

(a/b)' = (a'*b-a*b')/b^2
0*x^2-5*(2x)/(x^2)^2 = -10x/x^4 = -10/x^3

5/x^2 = 5x^-2 = -10x^-3

-10/x^3