d/dx
[(x^3 + 5x)(x^2 − x)]
x = 2
10 pts!!!!!
[(x^3 + 5x)(x^2 − x)]
x = 2
10 pts!!!!!
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d/dx((x^3+5 x) (x^2-x)) = x (5 x^3-4 x^2+15 x-10)
so when x = 2, the answer is 88
so when x = 2, the answer is 88
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this looks like the product rule:
uv
to do that you would u'v+uv'
so
(3x^2 + 5)(x^2-x) + (x^3 + 5X) (2x)
which comes out to
5x^4- 3x^3+ 15x^2 -5x
hope that helps
uv
to do that you would u'v+uv'
so
(3x^2 + 5)(x^2-x) + (x^3 + 5X) (2x)
which comes out to
5x^4- 3x^3+ 15x^2 -5x
hope that helps
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(x^3 + 5x)(x^2 -x)
=> x^5 +5x^3 -x^3 - 5x^2
=>x^5 + 4x^3 - 5x^2
=>5x^4+12x^2 -10x
when x=2
=> 80 + 48 - 20
=> 108
=> x^5 +5x^3 -x^3 - 5x^2
=>x^5 + 4x^3 - 5x^2
=>5x^4+12x^2 -10x
when x=2
=> 80 + 48 - 20
=> 108