How would you solve equations like these:
5^(2x)+5^x-12=0
I know you have to use logarithms but how? It says to find the solution in terms of natural logarithms.
Please and thank you.
5^(2x)+5^x-12=0
I know you have to use logarithms but how? It says to find the solution in terms of natural logarithms.
Please and thank you.
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5^(2x) + 5^x - 12 = 0
(5^x + 4)(5^x - 3) = 0
5^x = -4 is not possible
5^x = 3 --> x = ln(3)/ln(5)
(5^x + 4)(5^x - 3) = 0
5^x = -4 is not possible
5^x = 3 --> x = ln(3)/ln(5)
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solve (5^x + 4)(5^x - 3) = 0