Can you help me with some Calculus
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Can you help me with some Calculus

[From: ] [author: ] [Date: 11-09-16] [Hit: ]
.if not given assume that limit exists,if not given to prove that...2.......
We're working on derivatives of trig functions, which I understand. I'm just no good at finding limits of these. Please show me how you did it.

1. lim x>0 (sin(cosx))/secx answer is sin1, but I need to know how to get there...

2. lim x>pi/4 (1-tanx)/(sinx-cosx) answer is -2^1/2 (or -root of 2)

Thank you for your help.

-
1.1st put x=0 and see if there is any anomaly .here there is not so sin(cos0)/sec0=sin1...if not given assume that limit exists,if not given to prove that...
2.but here it comes in 0/0 form,so ue L'hospital law....see wikipedia...'
1-tanx/sinx-cosx=(cosx-sinx)/cosx(sinx…
so limx->pi/41/cosx=√2....
1
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