We're working on derivatives of trig functions, which I understand. I'm just no good at finding limits of these. Please show me how you did it.
1. lim x>0 (sin(cosx))/secx answer is sin1, but I need to know how to get there...
2. lim x>pi/4 (1-tanx)/(sinx-cosx) answer is -2^1/2 (or -root of 2)
Thank you for your help.
1. lim x>0 (sin(cosx))/secx answer is sin1, but I need to know how to get there...
2. lim x>pi/4 (1-tanx)/(sinx-cosx) answer is -2^1/2 (or -root of 2)
Thank you for your help.
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1.1st put x=0 and see if there is any anomaly .here there is not so sin(cos0)/sec0=sin1...if not given assume that limit exists,if not given to prove that...
2.but here it comes in 0/0 form,so ue L'hospital law....see wikipedia...'
1-tanx/sinx-cosx=(cosx-sinx)/cosx(sinx…
so limx->pi/41/cosx=√2....
2.but here it comes in 0/0 form,so ue L'hospital law....see wikipedia...'
1-tanx/sinx-cosx=(cosx-sinx)/cosx(sinx…
so limx->pi/41/cosx=√2....