I need help with math. Finding the standard form of the equation
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I need help with math. Finding the standard form of the equation

[From: ] [author: ] [Date: 11-09-16] [Hit: ]
Can anyone help me by writing out the steps to the problem. I would appreciate any help. Thank you in advance :)-Yup, you got the first part right. All you need to find is r² (radius squared) now.Standard Form of the equation a circle,......
Find the standard form of the equation of the specified circle.
Center: (2, -7); point on circle: (-2, -5)

I know that part of the equation is (x-2)^2 + (y- -7)^2=
But I don' know what it equals to. Can anyone help me by writing out the steps to the problem. I would appreciate any help. Thank you in advance :)

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Yup, you got the first part right. All you need to find is r² (radius squared) now.

Standard Form of the equation a circle, as you know, is (x - h)² + (y - k)² = r²

You're provided your center already: (2, -7)
Your equation is now (x - 2)² + (y + 7)² = r²

You're also provided a point, (-2, -5). You can insert this point into your equation, and then solve for r².

(-2 - 2)² + (-5 + 7)² = r²
(-4)² + (2)² = r²
20 = r²

Your equation is now...

(x - 2)² + (y + 7)² = 20

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It would seem that the radius of the circle is what you need to find. The formula calls for plugging in the center as x and y and the coordinates of a point (h,k). You have the center co-ordinates properly located in your formula...
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