How do you express y = (1/4)x² - 5x + 8 in the form (x-x0)² = 4A(y-y0)
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How do you express y = (1/4)x² - 5x + 8 in the form (x-x0)² = 4A(y-y0)

[From: ] [author: ] [Date: 11-09-16] [Hit: ]
......
the 0s are meant to be in subscript.

thanks

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y = (1/4)x² - 5x + 8
4y = x^2 - 20x + 32
4y = (x - 10)^2 - 100 + 32
4y + 68 = (x - 10)^2
(x - 10)^2 = 4(y + 17)

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y = (1/4)x² - 5x + 8

4y = x^2 - 20x + 32

4y = (x - 10)^2 - 100 + 32

4y + 68 = (x - 10)^2
(x - 10)^2 = 4(y + 17)
1
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