thx for your help! will rate answers!
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using the product rule
y'(x)= cos 9x[d/dx sin(6x)]+sin6x[d/dx cos9x]
then applying the chain rule
y'(x)=cos 9x* (cos 6x*[d/dx 6x])-sin6x*(sin9x(d/dx 9x))
simplifying we get
Answer: y'(x)= 6cos9x*cos6x - 9sin6x*sin9x
If you are having some trouble with derivatives I would strongly recommend watching some videos on youtube, they helped me out a lot when I was first learning this. Hope it makes sense!
y'(x)= cos 9x[d/dx sin(6x)]+sin6x[d/dx cos9x]
then applying the chain rule
y'(x)=cos 9x* (cos 6x*[d/dx 6x])-sin6x*(sin9x(d/dx 9x))
simplifying we get
Answer: y'(x)= 6cos9x*cos6x - 9sin6x*sin9x
If you are having some trouble with derivatives I would strongly recommend watching some videos on youtube, they helped me out a lot when I was first learning this. Hope it makes sense!