Solve x^2 + 2x = -2 by graphing and indicate the roots.
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Solve x^2 + 2x = -2 by graphing and indicate the roots.

[From: ] [author: ] [Date: 11-09-01] [Hit: ]
a = 1, b = 2,Check out the discriminant of the quadratic formula, b^2 - 4ac, to see if this thing has real roots.b^2 - 4ac = 2^2 - 4(1)(2) = 4 - 8 = - 4.......
a. between -3 and -2 and between 0 and 1
b. between -1 and 0 and between 2 and 3
c. no real solutions
d. -1, 1

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Graphing is a pain in the backside. Use wolfram alpha to show graphs.

However, using algebra (a sneaky tactic) there are no real solutions.

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A picture helps.

Put your quadratic in standard form: ax^2 + bx + c = 0

x^2 + 2x = - 2

x^2 + 2x + 2 = 0

a = 1, b = 2, c = 2

Check out the discriminant of the quadratic formula, b^2 - 4ac, to see if this thing has real roots.

b^2 - 4ac = 2^2 - 4(1)(2) = 4 - 8 = - 4.

The discriminant is negative. Your parabola has complex roots.

Sketch your parabola opening upward, with the vertex above the x-axis.
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