Hey im having a little trouble, i cant figure this problem out, a(3tx-2b)=c(dx-2) , you have to solve for x
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a(3tx-2b)=c(dx-2)
Distribute:
3atx - 2ab = cdx - 2c
Move all x to one side
3atx - cdx = 2ab - 2c
Factor out x
x(3at - cd) = 2ab - 2c
move other stuff to the other side.
x = (2ab - 2c) / (3at - cd)
Distribute:
3atx - 2ab = cdx - 2c
Move all x to one side
3atx - cdx = 2ab - 2c
Factor out x
x(3at - cd) = 2ab - 2c
move other stuff to the other side.
x = (2ab - 2c) / (3at - cd)
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3atx -2ab = cdx - 2c
3atx - cdx - 2ab = -2c
3atx -cdx = 2ab - 2c
x(3at - cd)= (2ab-2c)
x=(2ab-2c)/(3at-cd)
3atx - cdx - 2ab = -2c
3atx -cdx = 2ab - 2c
x(3at - cd)= (2ab-2c)
x=(2ab-2c)/(3at-cd)