Lets say I have a right triangle ABC. angle C=90*. side c=25, and side b=24. How do I find side a, and how do I find the measures of the other angles. And would it be possible to find the angles without using one of those special Trig Table things, since I don't have one and won't be supplied one.
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sin90/25=sinB/24
24sin90/25=
sin^-1(24/25)=B
B=73.7º
90+73.7
A=16.3º
x^2+24^2=25^2
x^2=49
x=7
24sin90/25=
sin^-1(24/25)=B
B=73.7º
90+73.7
A=16.3º
x^2+24^2=25^2
x^2=49
x=7
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Well we would have to know which side is the hypotenuse. (the side that is diagonal).
From there you would use the Pythagorean theorem to get the missing side. (a^2+b^2=c^2)
To get the angles, you would use inverse trig functions. For example, since sinθ=opp/hyp, you would get θ (the angle) by running sin^(-1)[opp/hyp]=θ
Without knowing which side is the hypotenuse, it's impossible to solve.
EDIT:
qѣπ is assuming side c is the hypotenuse.
From there you would use the Pythagorean theorem to get the missing side. (a^2+b^2=c^2)
To get the angles, you would use inverse trig functions. For example, since sinθ=opp/hyp, you would get θ (the angle) by running sin^(-1)[opp/hyp]=θ
Without knowing which side is the hypotenuse, it's impossible to solve.
EDIT:
qѣπ is assuming side c is the hypotenuse.