An object of mass 2.0 kg is placed at rest at the edge of the smooth horizontal table.The edge is 50cm above the floor.An object B of mass 1.5 kg moves towards object A at constant speed 2.0 m/s.After colliding with object A, object B moves in the opposite direction at speed 0.8m/s.
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conservation of momentum
2 * 0 + 1.5 * 2 = 2 *u - 1.5 * 0.8
u = 2.1 m/s
s= 0.5m; u'=0
s = u't + 0.5 * 9.81 * t^2
0.5 = 0 + 0.5 * 9.81 * t^2
t=0.319s
horizontal distance traveled by object A
= 0.319 * 2.1
= 0.6699m
answer
2 * 0 + 1.5 * 2 = 2 *u - 1.5 * 0.8
u = 2.1 m/s
s= 0.5m; u'=0
s = u't + 0.5 * 9.81 * t^2
0.5 = 0 + 0.5 * 9.81 * t^2
t=0.319s
horizontal distance traveled by object A
= 0.319 * 2.1
= 0.6699m
answer